No carry, no fingerprint
Bitwise ops have no carry. Each bit stands alone, so nothing flows between the low and high halves of a u64. A 64-bit AND, OR, or XOR is therefore just the 32-bit instruction run twice, once on each half:
and r4, r4, r6 # low half
and r3, r3, r5 # high half
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With a in r3:r4 and b in r5:r6, and r4, r4, r6 ANDs the low words and and r3, r3, r5 ANDs the high words, leaving the result in r3:r4. Swap the mnemonic for or or xor and you have or_64 or xor_64, the same two-instruction shape.
Because there's no carry, these are the hardest 64-bit ops to identify. That pair of ands is byte-for-byte what you'd get ANDing two unrelated 32-bit pairs, with no carrying instruction and no helper call to mark it as one wide value.
You usually can't prove width from the bitwise op alone; the surrounding code settles it. A result flowing into an adde, a mulhwu burst, a __div2u call, or a 64-bit compare is what tells you the AND was working on a 64-bit value.
Your task
Write and_64 to match the target.