No carry, no fingerprint
Bitwise operations treat each bit independently — there's no carry or borrow to flow between the two halves. So a 64-bit AND, OR, or XOR is simply the ordinary 32-bit instruction applied once per half:
and r4, r4, r6 # low half
and r3, r3, r5 # high half
blr
or_64 and xor_64 are identical with or / xor substituted in.
This makes the bitwise ops the least identifiable 64-bit operations. Two back-to-back ands on neighbouring registers are exactly what you'd get from ANDing two pairs of unrelated 32-bit values — there's no carrying instruction, no intrinsic call, nothing that says "this is one 64-bit value."
The practical takeaway: you usually can't prove a value is 64-bit from a bitwise op alone. You confirm it from the company it keeps — if the result flows into an adde, a mulhwu burst, a __div2u call, or a 64-bit compare, then you know the bitwise op was operating on a 64-bit value too.
Your task
Write and_64 to match the target.